Tennis - World No. 4 Stan Wawrinka is one win away from repeating as Chennai Open champion and will take on qualifier Aljaz Bedene in Sunday's final. The Swiss player overcame the in-form Belgian David Goffin 7-5, 6-3 in the second semi-final of the day.
In the first semi-final, 156th ranked Bedene saved four matchpoints as he upset the No. 3 seed Roberto Bautista Agut 3-6, 6-3, 7-6(8). Bedene, originally from Slovenia but in the process of switching nationalities to Great Britain, had to come through the qualifying draw and is now through to his first career ATP singles final.
Wawrinka, on the other hand, will be contesting his 17th ATP singles final. Bedene saved the first two matchpoints at 15-40 in the tenth game of the final set and two more in the tiebreak before winning on his first. Agut is the third seeded player that Bedene has beaten this week.
Wawrinka and Bedene will be meeting for the third time on Sunday, have split their two career meetings thus far and ironically all three have come in Chennai. Bedene defeated the Swiss player in the quarter-finals in 2013 while Wawrinka gained his revenge in the same round in 2014.
In the doubles draw, Yen-Hsun Lu and Jonathan Marray beat Purav Raja and Adil Shamasdin 5-7, 6-3, 10-8. Lu/ Marray will meet the top seeds Leander Paes/ Raven Klaasen in Sunday's final. 41-year-old Paes will be hoping to win the Chennai doubles title for a record seventh time. ALSO READ - WAWRINKA SAYS HE IS LUKCY TO PLAY IN THE SAME ERA AS FEDERER, NADAL, DJOKOVIC